f(2)=-2(2)^2-2(2)-6

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Solution for f(2)=-2(2)^2-2(2)-6 equation: 



f(2)=-2(2)^2-2(2)-6

We move all terms to the left:

f(2)-(-2(2)^2-2(2)-6)=0

We add all the numbers together, and all the variables

f^2+512=0

a = 1; b = 0; c = +512;
Δ = b2-4ac
Δ = 02-4·1·512
Δ = -2048
Delta is less than zero, so there is no solution for the equation

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